maths
posted by albert .
Choose the option that gives the solution of the initialvalue problem
dy
dx=(1 + 2 cos2x^2)/y (y > 0), y= 1 when x = 0.
Options
A y = 1+ 2sin^2 x
B y = (1 + 2 sin x)^2
C y = (4x + cos(2x))^2
D y = 4x + cos^2 x
E y =sqrt(4x + cos(2x)
F y =sqrt(1 + 4x + sin(2x))
G y =1/(sqrt(2x + cos(2x))
H y = 1/(sqrt(1 + sin(2x))
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