Algebraic
posted by rian .
Determine the roots of the quadratic equation by completing the square. Solve for exact solutions and approximate solutions. Check your solutions.
Y=x26x12

Algebraic 
Steve
x^26x  12
(x^26x+9)  129
(x3)^2  21
so, setting
(x3)^2  21 = 0
(x3)^2 = 21
x3 = ±√21
x = 3±√21
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