Algebra

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Check My answers Please-

1. 3(y + 1) for y = 2
a.6
b.9***
c.7
d.8

2. d + g/h for d = 45, g = 18, and h = 9
a.6***
b.7
c.3
d.4

3.The cost in dollars of a class party is 59 + 13n, where n is the number of people attending. What is the cost for 44 people?
a.$116
b.$587
c.$767
d.$631***

4.write a word phrase for p-4
a. a number plus 4
b. a number decreased by 4 ***
c. the product of a number and 4
d. the quocent of a number and 4

5.A basketball player scores 10 points per game. Write an algebraic expression to show how many points she might score in n games
a. 10n***
b. 10 + n
c.10 divided by n
d. n - 10

I skipped 6 for a reason

7. Jamie owns about 3 times as many books as Carly. Jamie owns 42 books. Write an equation and use it to estimate the n number of books Carly owns
a. 3n = 42: about 14 books***???
b. n + 2 = 42: about 40 books
c. n divided by 3 = 42: about 126 books
d. n - 2 = 42: about 44 books

  • Algebra -

    Pls respond! I will tank you forever if you do! :) Mrs. Sue?

  • Algebra -

    oops! I meant 7 for number 2

  • Algebra -

    Anyone there?

  • Algebra -

    Mrs. Sue?

  • Algebra -

    1. good

    2. 45 + 18/9 = 45 + 2 = 47 (typo?)

    3. right

    4. right

    5. right

    6. C = J/3 = 42/3 = 14

  • Algebra -

    Thank you so so much!

  • Algebra -

    *hugs*

  • Algebra -

    Please note that my title is Ms., not Mrs.

    Yes, all of your answers are right.

  • Algebra -

    I have another question that I hope you don't mind answering its -
    Patricia owned so many posters that she decided to sell 77 of them to her friends. After selling the posters she still had 186 left. Write and solve the equation to find the number of posters Patricia had originally
    a. p + 77 = 186: 109 posters
    b. p + 186 = 77: 109 posters
    c. p - 77 = 186: 263 posters ***
    d. p + 186 = 77: 263 posters

  • Algebra -

    I care Ms. Sue! Sorry about that

  • Algebra -

    :-)

    Yes, your last problem is correct.

  • Algebra -

    ok mrs. sue

  • Algebra -

    ok mrs. sue

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