Algebra
posted by Abigail .
Check My answers Please
1. 3(y + 1) for y = 2
a.6
b.9***
c.7
d.8
2. d + g/h for d = 45, g = 18, and h = 9
a.6***
b.7
c.3
d.4
3.The cost in dollars of a class party is 59 + 13n, where n is the number of people attending. What is the cost for 44 people?
a.$116
b.$587
c.$767
d.$631***
4.write a word phrase for p4
a. a number plus 4
b. a number decreased by 4 ***
c. the product of a number and 4
d. the quocent of a number and 4
5.A basketball player scores 10 points per game. Write an algebraic expression to show how many points she might score in n games
a. 10n***
b. 10 + n
c.10 divided by n
d. n  10
I skipped 6 for a reason
7. Jamie owns about 3 times as many books as Carly. Jamie owns 42 books. Write an equation and use it to estimate the n number of books Carly owns
a. 3n = 42: about 14 books***???
b. n + 2 = 42: about 40 books
c. n divided by 3 = 42: about 126 books
d. n  2 = 42: about 44 books

Algebra 
Abigail
Pls respond! I will tank you forever if you do! :) Mrs. Sue?

Algebra 
Abigail
oops! I meant 7 for number 2

Algebra 
Abigail
Anyone there?

Algebra 
Abigail
Mrs. Sue?

Algebra 
PsyDAG
1. good
2. 45 + 18/9 = 45 + 2 = 47 (typo?)
3. right
4. right
5. right
6. C = J/3 = 42/3 = 14 
Algebra 
Abigail
Thank you so so much!

Algebra 
Abigail
*hugs*

Algebra 
Ms. Sue
Please note that my title is Ms., not Mrs.
Yes, all of your answers are right. 
Algebra 
Abigail
I have another question that I hope you don't mind answering its 
Patricia owned so many posters that she decided to sell 77 of them to her friends. After selling the posters she still had 186 left. Write and solve the equation to find the number of posters Patricia had originally
a. p + 77 = 186: 109 posters
b. p + 186 = 77: 109 posters
c. p  77 = 186: 263 posters ***
d. p + 186 = 77: 263 posters 
Algebra 
Abigail
I care Ms. Sue! Sorry about that

Algebra 
Ms. Sue
:)
Yes, your last problem is correct. 
Algebra 
terrious
ok mrs. sue

Algebra 
terrious
ok mrs. sue
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