posted by Shehzad .
In a software company 30% workers are BTeach holders 25%are m.ba and 20% hold both these degrees. If 325 workers are without any professional degree how many workers are there in the company in all.
30% + 25% + 20% = 75% hold degrees; therefore, 100%- 75% = 25% that do not
x = number of workers
0.25x = 325. Solve for x.
I disagree ..
number(BT or MBA) = 30%+25% - 20% = 35%
(we can't count the 20% twice )
so 65% are without degrees
x = 500
I worried about counting them twice, also; however, I finally decided we had four separate and distinct groups. One pool of 30% had BT, one pool of 25% had MBA, a third pool of 20% had both (this is a separate group that I didn't overlap with the other three), which left a fourth pool of 25% with no degrees. My interpretation may not be right but that's my rationale. By having four pools I was trying to avoid counting them twice.
In these kind of questions, when they state that 30% workers are BTeach holders, we don't assume that it is 30% exclusively.
e.g. When I say, that 8% of boys play football, that doesn't mean that they can't play some other sport as well.
In a Venn diagram for this question, I would draw two intersecting circles, label the intersection 20%, the "only BT" circle as 30-20 or 10% , and the "only MBA" section as 25-20 or 5%.
So that would add up to (20+10+5)% or 35% leaving 65% without those two degrees.
then .65x = 325
I agree with your interpretation.