Algebra 1

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Micah Beasley invested $10,000 for one year, part at 10% annual interest and part at 14% annual interest. Vos total interest for the year was $1,280. How much money did he invest at each rate?

  • Algebra 1 -

    let the part invested at 10% be x
    let the part invested at 14% be 10000-x

    solve for x

    .1x + .14(10000-x) = 1280

    let me know what you get, so I can check it

  • Algebra 1 -

    x at 10%, and y at 14%

    x + y = 10000

    .10 x + .14 y = 1280 ... multiplying by -10 ... -x - 1.4y = -12800

    adding equations (to eliminate x) ... -.4 y = -2800

    solve for y , then substitute back to find x

  • Algebra 1 -

    thank toi!

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